Equilibre D 39un Solide Soumis A 3 Forces Exercice Corrige Pdf Exclusive Review

If a solid is in equilibrium under the action of three forces modified cap F with right arrow above sub 1 modified cap F with right arrow above sub 2 modified cap F with right arrow above sub 3 Vector Condition : The sum of the force vectors is equal to the null vector:

La condition d'équilibre donne deux équations selon les axes : Calculs numériques : Réponse finale L'intensité de la tension du fil est de et la réaction normale du plan est de If a solid is in equilibrium under the

✅ Tension = 100 N, Reaction = 100 N at 36.9° above left horizontal. So ( R_W = 800 / 1

But from geometry, slope of ( R_F ) from O to P: ( \Delta y / \Delta x = 4.33/2.1875 = 1.98 ). Thus ( \frac800R_W = 1.98 ) (since vertical component up = 800 N, horizontal component left = ( R_W ) N). So ( R_W = 800 / 1.98 \approx 404 , N ). the third must also be parallel

⚠️ If two forces are parallel, the third must also be parallel, and their magnitudes must balance (special case).