Introduction To Contextual Maths | In Chemistry .pdf

If ( [\textH^+] = 3.2 \times 10^-5 , \textM ), find pH. [ \textpH = -\log_10(3.2 \times 10^-5) = -(\log_103.2 + \log_1010^-5) = -(0.505 - 5) = 4.495 ]